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100=16x-2x^2
We move all terms to the left:
100-(16x-2x^2)=0
We get rid of parentheses
2x^2-16x+100=0
a = 2; b = -16; c = +100;
Δ = b2-4ac
Δ = -162-4·2·100
Δ = -544
Delta is less than zero, so there is no solution for the equation
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